select s.*  
from ( 
    select b.*, row_number() over (partition by b.[重复字段] order by b.[排序字段]) as group_idx  
    from table_name b
) s
where s.group_idx = 1

Logo

腾讯云面向开发者汇聚海量精品云计算使用和开发经验,营造开放的云计算技术生态圈。

更多推荐