python 数字整除

Given a range (which is 1 to 1000) and we have print all numbers which are divisible bye 7 and not divisible by 5 in python.

给定一个范围(1到1000)，我们打印了所有在python中可被7整除而不能被5整除的数字。

Example:

例：

    Input:
    Given input range is 1 to 1000

    Output:
    7, 14, 21, 28, 42, 49, 56, ...

Logic:

逻辑：

• To implement this logic, we will use a for and in loop with range() method. The statement of range() method with the minimum to maximum range is range(begin, end+1).

  为了实现此逻辑，我们将使用for和in循环with range()方法。 范围从最小到最大的range()方法的语句是range(begin，end + 1) 。

• And, check the condition, that value should be divisible by 7 and should not be divisible by 5 (example code: ((cnt%7==0) and (cnt%5!=0)) ).

  并且，检查条件，该值应可被7整除，而不能被5整除(示例代码： ((cnt％7 == 0)和(cnt％5！= 0))) 。

• If condition is true, print the numbers.

  如果条件为真，则打印数字。

Program:

程序：

# define range in variables
# so that we can change them anytime
begin 	= 1 
end 	= 1000

# loop to check and print the numbers
# which are divisible by 7 and not 
# divisible by 5
for cnt in range(begin, end+1):
	if( cnt%7==0 and cnt%5!=0 ):
		print cnt, # command after cnt will print space

Output

输出量

    7 14 21 28 42 49 56 63 77 84 91 98 112 119 126 
    133 147 154 161 168 182 189 196 203 217 224 231 
    238 252 259 266 273 287 294 301 308 322 329 336 
    343 357 364 371 378 392 399 406 413 427 434 441 
    448 462 469 476 483 497 504 511 518 532 539 546 
    553 567 574 581 588 602 609 616 623 637 644 651 
    658 672 679 686 693 707 714 721 728 742 749 756 
    763 777 784 791 798 812 819 826 833 847 854 861 
    868 882 889 896 903 917 924 931 938 952 959 966 
    973 987 994

翻译自: https://www.includehelp.com/python/print-all-numbers-between-1-to-1000-which-are-divisible-by-7-and-must-not-be-divisible-by-5.aspx

python 数字整除