每日一题洛谷P5741 【深基7.例10】旗鼓相当的对手 - 加强版c++
【代码】每日一题洛谷P5741 【深基7.例10】旗鼓相当的对手 - 加强版c++
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#include<iostream>
#include<cstring>
#include<cmath>
using namespace std;
struct student {
string name;
int a;
int b;
int c;
int sum;
};
struct student s[1000];
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) cin >> s[i].name >> s[i].a >> s[i].b >> s[i].c;
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
s[i].sum = s[i].a + s[i].b + s[i].c;
s[j].sum = s[j].a + s[j].b + s[j].c;
if (abs(s[i].sum - s[j].sum) <= 10) {
if (abs(s[i].a - s[j].a) <= 5 && abs(s[i].b - s[j].b) <= 5 && abs(s[i].c - s[j].c) <= 5) {
cout << s[i].name << " " << s[j].name << endl;
}
}
}
}
return 0;
}


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